Driving theory questions
If you are driving at 100 km/h and increase your speed to 110 km/h, how much time do you gain per 10 km?
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Driving Licence Book (19th Edition, page 84):
“If you increase your average speed by 10 km/h, the time gain per 10 km will be:
– approximately 1 minute at speeds under 90 km/h
– approximately ½ minute at speeds over 90 km/h”
In all likelihood, you will not need to know the following mathematical calculations for the real test. It is enough to know that the time gain is minimal.
Method 1
| Colour codes for the figures (easier to keep track of them) | |
| Original speed | 100 km/h |
| New speed | 110 km/h |
| Minutes per hour (since the speed is km/h, kilometres per hour) | 60 minutes |
| Number of kilometres | 10 km |
We first calculate how many minutes it takes to travel 1 km at both speeds:
- 60 / 100 = it takes 0.6 minutes to travel 1 km
- 60 / 110 = it takes 0.54 minutes to travel 1 km
It is therefore takes slightly less time with the higher speed. The difference is:
- 0.6 - 0.54 = 0.06 minutes faster per km when travelling at 110 km/h compared with 100 km/h.
However, the question is how much time you gain per 10 km, not per km. Therefore, recalculate the time gain per 10 km:
- 0.06 * 10 = 0.6 minutes time gain per 10 km
Now it is really done. It is however easier to understand if the answer is recalculated to seconds:
- 0.6 * 60 = 36 seconds
Method 2
| Colour codes for the figures (easier to keep track of them) | |
| Original speed | 100 km/h |
| New speed | 110 km/h |
| Distance | 10 km = 10,000 metres |
| Fixed conversion rate km/h to m/s | 3.6 times |
Formula for calculation of time:
- Distance / speed = time
For the formula to work requires us to use metres instead of 10 km and metres per second (m/s) instead of kilometres an hour (km/h). The speeds are therefore recalculated to m/s:
- 100 / 3.6 = 27.78 m/s
- 110 / 3.6 = 30.56 m/s
Only now can we use the formula Distance / speed = time:
- 10,000 / 27.78 = 360 s
- 10,000 / 30.56 = 327 s
We can then work out the time difference between both speeds:
- 360 - 327 = 33 seconds
This is an example of one of the driving theory questions at Körtkortonline.se.
There is also a driving licence book online (2026).
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