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Is it true that 100 cl of light beer (3.5%) contains as much alcohol as 50 cl of strong beer (7.0%)?
“The amount of [...] pure spirits (40 %) that a strong beer or a glass of wine corresponds to [...] can be calculated with a formula (percentage by volume * the volume in cl * 0.025).” (MHF)
Light beer: (3.5 * 50 * 0.025) * 2 = 8.75 cl spirits
Strong beer: (7.0 * 50 * 0.025) * 1 = 8.75 cl spirits
So the answer is yes. Note however that this does not mean you will experience the exact same intoxication from drinking two light beers as with one strong beer.
(0.025 is the same as dividing by 40)
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